Hi,
I am using Ranorex with my .NET desktop application. I have a menu on the top of my main page and when I do File->New it takes some time to load/activate the form. In the second step I need to click on one button.
I am using the follwing script and second statement is causing error as FILE->NEW is taking some time.
ds.TestRepository.MenuItemNew.Click(Location.UpperLeft);
ds.TestRepository.ButtonAdd_Area.Click();
I don't want to put the specific timeout here. I am expecting something in
Core which automatically detects that the thread/application is busy before taking button click action.
Should I use find here?
Delay between actions
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Support Team
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Hi,
The next updated preview version will provide some configuration settings. There will be a search timeout setting available for each item of the object repository editor. The currently available version generates the repository code using a hard coded search timeout for the whole repository.
Normally you should not need to change the repository code! As a workaround (until next version update) you can change the gemerated code to increase the search timeout manually.
What we can't do is to handle performance states of applications. Ranorex focuses on accessing application information using their graphical user interface.
best regards,
Christoph
Ranorex Support Team
The next updated preview version will provide some configuration settings. There will be a search timeout setting available for each item of the object repository editor. The currently available version generates the repository code using a hard coded search timeout for the whole repository.
Code: Select all
static int _timeout = 1000;What we can't do is to handle performance states of applications. Ranorex focuses on accessing application information using their graphical user interface.
best regards,
Christoph
Ranorex Support Team
