How to get the Test case name if smart folder is present in the testcase?

[praneet]

Hi,

I want to get the testcase name when smart folder is present in the test case.I tried using the below code.

Code: Select all

var curTestCase = (TestCaseNode)TestSuite.CurrentTestContainer;
			string tcName = curTestCase.Name;
			 TC = TestSuite.Current.GetTestContainer(tcName);

but the above code is returning the smartfolder nameinstead of test case name
Can anyone provide me the solution.Thanks in advance!!

[odklizec]

Hi,

I'm using code like this (used in codemodule), which is placed anywhere in test and which returns 'root' test case name:

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TestModuleLeaf curModule = (TestModuleLeaf)TestModuleLeaf.Current;
string rootTCName = CommonCodeCollection.UserCodeCollection.SystemLib.GetRootTestCaseName(curModule);

And here is the actual GetRootTestCaseName method:

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public static string GetRootTestCaseName(TestSuiteEntry entry)
{
    string rootname = string.Empty;
    while (entry != null)
    {
        if ((entry is TestCaseNode) && (!(entry as TestCaseNode).IsRootTestCase && !(entry as TestCaseNode).IsSmartFolder))
        {
            rootname = entry.Name;
        }
            entry = entry.Parent;
    }
    return rootname;	
}

[praneet]

Awesome!It works .Thank you

How can we get the CurrentRowIndex after getting the testcase name for the above scenario if the datasource is Excel data connector?
For eg:

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var curTestCase = (TestCaseNode)TestSuite.CurrentTestContainer;
			string tcName = curTestCase.Name;
			TC = TestSuite.Current.GetTestContainer(tcName);
			
			int rowId1 = TC.DataContext.CurrentRowIndex;

[odklizec]

Hi,

You are welcome. As for the second question, I'm using code like you posted and it works OK? So if you want to use the root TC name, obtained with the code I posted, simply remove the first two lines from your code and replace tcName with rootTCName. This should do the trick.